y^2+5y-4y=-6

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Solution for y^2+5y-4y=-6 equation: 



y^2+5y-4y=-6

We move all terms to the left:

y^2+5y-4y-(-6)=0

We add all the numbers together, and all the variables

y^2+y+6=0

a = 1; b = 1; c = +6;
Δ = b2-4ac
Δ = 12-4·1·6
Δ = -23
Delta is less than zero, so there is no solution for the equation

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